Please solve q 61?

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1 Answer
Apr 19, 2018

The magnitude of the acceleration is F_1/mF1m

Explanation:

The three forces acting together kept the particle in equilibrium. Thus, there resultant was zero. So

vec{F}_1+ vec F_2+vec F_3 = 0F1+F2+F3=0

When the force vec F_1F1 is removed, the net force is

vec F_2 + vec F_3 = -vec F_1F2+F3=F1

Thus the acceleration is

vec a = - (vec F_1)/m qquad implies qquad |vec a| = |vec F_1|/m