Please solve q 69?

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Answer 1 · 2018-04-26T11:38:12

The answer is $option (c)$ $"option (c)"$

Let the cross section of the pipe be $= (a) m^{2}$ $=(a)m^2$

Let the density of water be $= (ρ) k g m^{- 3}$ $=(rho)kgm^-3$

The speed of the water is $= (v) m s^{- 1}$ $=(v)ms^-1$

The mass of water transported is

$q_{m} = (v a ρ) m^{3} s^{- 1}$ $q_m=(varho) m^3s^-1$

The kinetic energy of the water is

$K E = \frac{1}{2} \times (v a ρ) \times v^{2} J s^{- 1}$ $KE=1/2xx(varho)xxv^2Js^-1$

This is the power

$P = \frac{1}{2} a ρ v^{3} W$ $P=1/2arhov^3W$

Therefore,

The power is proportional to $v^{3}$ $v^3$

The answer is $option (c)$ $"option (c)"$