Question

Points D(-4, 6), E(5, 3), and F(3, -2) are the vertices of triangle DEF. How do you find the perimeter of the triangle?

Answer 1

`p=sqrt(113)+sqrt(29)+sqrt(90)`

Explanation:

After the Formula
`sqrt((x_2-x_1)^2+(y_2-y_1)^2)`
We get
`DE=sqrt(7^2+8^2)=sqrt(113)`
`FE=sqrt(2^2+5^2)=sqrt(29)`
`DE=sqrt(9^2+3^3)=sqrt(90)`