Prove that?

#arcsin(x)^3 + arccos(x)^3 = alpha x # has no roots for #alpha<1/32# and #alpha>7/8#

1 Answer
May 28, 2018

I don't think it's true.

Explanation:

See this example%5E3+%2B+arccos(x)%5E3,+10x), in which I plot #arcsin^3(x)+arccos^3(x)# and #10x#.

According to your claim, they should have no intersection, since #alpha=10>7/8#, but as you can see, they have.