Pure copper may be produced by the reaction of copper(I) sulfide with oxygen gas as follows: $C u_{2} S (s) + O_{2} (g) \to 2 C u (s) + S O_{2} (g)$ $Cu_2S(s) + O_2(g) -> 2Cu(s) + SO_2(g)$ . What mass of copper(I) sulfide is required in order to prepare 0.650 kg of copper metal?

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Pure copper may be produced by the reaction of copper(I) sulfide with oxygen gas as follows: $C u_{2} S (s) + O_{2} (g) \to 2 C u (s) + S O_{2} (g)$ $Cu_2S(s) + O_2(g) -> 2Cu(s) + SO_2(g)$ . What mass of copper(I) sulfide is required in order to prepare 0.650 kg of copper metal?

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Answer 1 · 2017-03-14T04:17:40

We require $≅ 732 \cdot g$ $~=732*g$ ore...................

Explanation:

You have given the stoichiometric equation that represents reduction of cuprous sulfide:

$C u_{2} S (s) + O_{2} (g) \to 2 C u (s) + S O_{2} (g)$ $Cu_2S(s) + O_2(g) rarr 2Cu(s) + SO_2(g)$

Sulfur is oxidized; copper and oxygen are reduced.

$Moles of copper = \frac{650 \cdot g}{63.55 \cdot g \cdot m o l^{- 1}} = 10.3 \cdot m o l$ $"Moles of copper"=(650*g)/(63.55*g*mol^-1)=10.3*mol$ .

Given the equation, there is HALF AN EQUIVALENT of copper ore, i.e. $5.11 \cdot m o l$ $5.11*mol$ of $C u_{2} S$ $Cu_2S$ are required.

And this represents a mass of $5.1 \cdot m o l \times 143.1 \cdot g \cdot m o l^{- 1}$ $5.1*molxx143.1*g*mol^-1$

$≅ 732 \cdot g$ $~=732*g$

I think the ore is the mineral $chalcosite$ $"chalcosite"$ , which is approx. 80% metal by mass. Because of the high metal content, this is one of the most valuable copper ores.

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Pure copper may be produced by the reaction of copper(I) sulfide with oxygen gas as follows: $C u_{2} S (s) + O_{2} (g) \to 2 C u (s) + S O_{2} (g)$ $Cu_2S(s) + O_2(g) -> 2Cu(s) + SO_2(g)$ . What mass of copper(I) sulfide is required in order to prepare 0.650 kg of copper metal?

1 Answer

Explanation:

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Pure copper may be produced by the reaction of copper(I) sulfide with oxygen gas as follows: Cu2S(s)+O2(g)→2Cu(s)+SO2(g)Cu_2S(s) + O_2(g) -> 2Cu(s) + SO_2(g). What mass of copper(I) sulfide is required in order to prepare 0.650 kg of copper metal?

1 Answer

Explanation:

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Pure copper may be produced by the reaction of copper(I) sulfide with oxygen gas as follows: $C u_{2} S (s) + O_{2} (g) \to 2 C u (s) + S O_{2} (g)$ $Cu_2S(s) + O_2(g) -> 2Cu(s) + SO_2(g)$ . What mass of copper(I) sulfide is required in order to prepare 0.650 kg of copper metal?