Q: Some data for the kinetic energy of ejected electrons as a function of the wavelength of the incident radiation for the photoelectron effect? with the relation between wavelength and KE in a graph.

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1 Answer
Feb 25, 2018

#h = 6.597 × 10^"-34"color(white)(l) "J·s"; Phi = "2.25 eV"#.

Explanation:

The equation for the photoelectric effect is

#color(blue)(bar(ul(|color(white)(a/a)hf = Φ + KEcolor(white)(a/a)|)))" "#

where

#h color(white)(ml)= # Planck's constant
#f color(white)(ml)= # the frequency of the incident light
#Phicolor(white)(m) =# the work function
#KE =# the kinetic energy of the ejected electron

We can rearrange the equation to get

#KE = hf - Phi#

Compare this equation with that for a straight line.

#KE = hf - Phi#
#color(white)(ll)ycolor(white)(ll) = mx + b#

Thus, a plot of #KE# vs #f# is a straight line with slope #h"# and #x#- intercept #Phi#.

I converted the wavelengths to frequencies and got the following dataset.

Data

The plot of #KE# vs #f# looked like this.

Graph

The calculated equation for the line is #KE = "0.004 118"f- 2.240#

The #y#-intercept is at

#"0 = "0.004 118"f- 2.2404#

#f = 2.2404/"0.004 118" = "544 THz"#

#"slope" = h =("0.004 118" color(red)(cancel(color(black)("eV"))))/(1 color(red)(cancel(color(black)("THz")))) ×(1.602 × 10^"-19" color(white)(l)"J")/(1 color(red)(cancel(color(black)("eV")))) × (1 color(red)(cancel(color(black)("THz"))))/(10^12color(white)(l) "s"^"-1") =#

#6.597 × 10^"-34"color(white)(l) "J·s"#

The experimental value for #h = 6.597 × 10^"-34"color(white)(l) "J·s"#.

The work function corresponds to the point where the excess kinetic energy of the electron is zero.

#0 = hf - Phi#

#Phi = hf = 6.626 × 10^"-34"color(white)(l) "J·"color(red)(cancel(color(black)("s"))) × 544 × 10^12 color(red)(cancel(color(black)("s"^"-1"))) = 3.60 × 10^"-19"color(white)(l) "J"#

In electron volts, the work function is

#Phi = 3.60 × 10^"-19" color(red)(cancel(color(black)("J"))) × "1 eV"/(1.602 × 10^"-19" color(red)(cancel(color(black)("J")))) = "2.25 eV"#