Reaction Of Toulene?

#C_6H_5CH_3#(Toulene) reacts with 2 equivalents of
#Cl_2# and then the product of that reaction reacts with #NaOH#(aqueous) gives aldehyde.

What does the 2 equivalents of #Cl_2# in the above reaction mean and what is its purpose in the reaction?

1 Answer
Mar 10, 2018

Here's what I get.

Explanation:

An equivalent of chlorine is the mass of #"Cl"_2# that will react with 1 mol of #"H"# atoms.

For example, consider the reaction:

#"C"_6"H"_5"CH"_2"-"color(red)("H") + color(red)("Cl")"-Cl" → "C"_6"H"_5"CH"_2"-Cl" + color(red)("HCl")#

One mole of chlorine reacts with one mole of #"H"# atoms, so one equivalent of chlorine is the same as one mole of chlorine.

The "2 equivalents of chlorine" tells you that there is enough chlorine to replace two moles of #"H"# atoms.

#underbrace("C"_6"H"_5"CH"_3)_color(red)("bottom") + "2Cl"_2 → underbrace("C"_6"H"_5"CHCl"_2)_color(red)("(dichloromethyl)benzene") + "2HCl"#

The base-catalyzed hydrolysis of a gem-dihalide gives an aldehyde or a ketone.

The first part of the reaction consists of an ordinary nucleophilic substitution to produce a gem-chlorohydrin.

The gem-chlorohydrin is unstable and quickly loses a molecule of #"HCl"#.

#"C"_6"H"_5"CHCl"_2 stackrelcolor(blue)("OH"^"-" color(white)(mm))(→) [underbrace("C"_6"H"_5"CH(OH)Cl")_color(red)("unstable intermediate")] → underbrace("C"_6"H"_5"CH(=O)")_color(red)("benzaldehyde")#