Right angled triangle with bottom side of the triangle is 40cm and the there are 2 angles attached to it, 40degrees and 90degrees, what is the length of the other 2 sides?

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Answer 1 · 2018-03-04T06:04:18

Given that a right angled triangle with bottom side of the triangle is 40cm and the there are 2 angles attached to it, 40degrees and 90degrees.

So adjacent w r to angle $40^{\circ}$ $40^@$ is $40$ $40$ cm.

So $\frac{opposite}{adjacent} = {tan 40}^{\circ}$ $"opposite"/"adjacent"=tan40^@$

Hence $opposite = 40 \cdot {tan 40}^{\circ} = 33.56$ $"opposite"=40*tan40^@=33.56$ cm.

Again

$\frac{hypotenuse}{adjacent} = {sec 40}^{\circ}$ $"hypotenuse"/"adjacent"=sec40^@$

So $hypotenuse = 40 \cdot {sec 40}^{\circ} = 52.21$ $"hypotenuse"=40*sec40^@=52.21$ cm