Simplify: #{(6^6)^4 -: (6^7)^0 xx[(6^2)^3]^2}^2 -: {[(6^3)^5xx(6^2)^3]^3 : [(6^3)^3]^4}^2#? Prealgebra Fractions Equivalent Fractions and Simplifying 1 Answer Shwetank Mauria Apr 26, 2016 #6^18# Explanation: #{(6^6)^4-:(6^7)^0xx[(6^2)^3]^2}^2-:{[(6^3)^5xx(6^2)^3]^3-:[(6^3)^3]^4}^2# = #{6^(24)-:6^0xx6^(12)}^2-:{[6^(15)xx6^6]^3-:[6^9]^4}^2# = #{6^(24-0+12)}^2-:{[6^(15+6)]^3-:6^36}^2# = #{6^(36)}^2-:{[6^(21)]^3-:6^36}^2# = #6^(72)-:{6^(63)-:6^36}^2# = #6^(72)-:{6^(63-36)}^2# = #6^(72)-:{6^(27)}^2# = #6^(72)-:6^(54)# = #6^(72-54)# = #6^18# Answer link Related questions What is 0.098 divided by 7? How do you find the fraction notation and simplify 16.6%? How do you convert #0.bar(45)# (meaning the #45# is being repeated) to a fraction? How do you convert 0.40 (40 repeating) to a fraction? How do you convert 8/15 to a decimal? How do you express #3/4, 7/16,# and #5/8# with the #LCD#? How do you simplify fractions? What is the simplified form of #30/42#? How do you subtract and simplify #9-5 1/3#? How do you add and simplify #5/7 + 3/4#? See all questions in Equivalent Fractions and Simplifying Impact of this question 1651 views around the world You can reuse this answer Creative Commons License