Sin (alpha-540°) Explain and Answer The Value?

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Sin (alpha-540°) Explain and Answer The Value?

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Answer 1 · 2018-06-10T10:14:02

$- sin (α)$ $-sin(alpha)$

Explanation:

Using
$sin (α - 540^{\circ}) = sin (α) \cdot cos (540^{\circ}) - cos (α) \cdot sin (540^{\circ})$ $sin(alpha-540^(circ))=sin(alpha)*cos(540^(circ))-cos(alpha)*sin(540^(circ))$
since

$cos (540^{\circ}) = - 1$ $cos(540^(circ))=-1$
$sin (540^{\circ}) = 0$ $sin(540^(circ))=0$
we get

$- sin (α)$ $-sin(alpha)$

Answer 2 · 2018-06-11T00:09:06

$- sin a$ $-sin a$

Explanation:

$sin (a - 540) = sin (a - 180 - 360) = sin (a - 180) = - sin a$ $sin (a - 540) = sin (a - 180 - 360) = sin (a - 180) = - sin a$

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Sin (alpha-540°) Explain and Answer The Value?

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