Question

Slope of a curve `y=x^2-3` at the point where `x=1`?

Answer 1

First you need to find `f'(x)`, which is the derivative of `f(x)`.

`f'(x)=2x-0=2x`

Second, substitute in the value of x, in this case `x=1`.

`f'(1)=2(1)=2`

The slope of the curve `y=x^2-3` at the `x` value of `1` is `2`.