Sodium chloride is $N a C l$ $NaCl$ , and sodium sulfide is $N a_{2} S$ $Na_2S$ . Why are there more sodium ions in the sulfide compound?

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Sodium chloride is $N a C l$ $NaCl$ , and sodium sulfide is $N a_{2} S$ $Na_2S$ . Why are there more sodium ions in the sulfide compound?

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Answer 1 · 2016-07-01T06:31:44

To give electric neutrality.

Explanation:

Sodium chloride is composed of $N a^{+}$ $Na^+$ ions and $C l^{-}$ $Cl^-$ ions. Now of course salt is neutral; and to ensure this sodium ion and chloride ions combine 1:1.

On the other hand, sulfur commonly forms an $S^{2 -}$ $S^(2-)$ ion. (Sulfur is a $Group VI$ $"Group VI"$ atom, and its chemistry is similar to oxygen, which certainly forms the $O^{2 -}, oxide$ $O^(2-)", oxide"$ ion.) Since sodium sulfide is a neutral salt, each sulfide ion requires $2 \times N a^{+}$ $2xxNa^+$ ions. Capisce?

Why are there $3$ $3$ sodium atoms in $N a_{3} P$ $Na_3P$ ?

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Sodium chloride is $N a C l$ $NaCl$ , and sodium sulfide is $N a_{2} S$ $Na_2S$ . Why are there more sodium ions in the sulfide compound?

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Explanation:

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Sodium chloride is NaClNaClNaCl, and sodium sulfide is Na_2SNa2SNa_2S. Why are there more sodium ions in the sulfide compound?

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Explanation:

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Sodium chloride is $N a C l$ $NaCl$ , and sodium sulfide is $N a_{2} S$ $Na_2S$ . Why are there more sodium ions in the sulfide compound?