Solve #4^(3x)=8^(x-2)#? Thank You.
1 Answer
Jul 2, 2017
Explanation:
#"express the bases on both sides in terms of " color(blue)"base 2"#
#rArr(2^2)^(3x)=(2^3)^(x-2)#
#rArr2^(6x)=2^((3x-6))#
#"since the bases are equal we can equate the exponents"#
#rArr6x=3x-6#
#rArr3x=-6#
#rArrx=-2#
#color(blue)"As a check"#
#"left side "=4^(-6)=1/(4^6)=1/4096#
#"right side "=8^(-4)=1/8^4=1/4096#
#rArrx=-2" is the solution"#