Solve by factoring? 12x^2-37x-780 =012x237x780=0

1 Answer
Sep 1, 2017

(3x+20)(4x-39)=0(3x+20)(4x39)=0

x =-20/3" or " x = 39/4x=203 or x=394

Explanation:

First determine whether there are rational factors.

a = 12" "b = -37 " "c = -780a=12 b=37 c=780

b^2 - 4ac = (-37)^2 -4(12)(-780) = 38809 = 197^2b24ac=(37)24(12)(780)=38809=1972

We need to find factors of 12 and 78012and780 whose products differ by 3737

The smaller the value if bb, the closer the factors are to sqrt(ac)ac

sqrt(12 xx 780) = sqrt9360 = 96.7 ~~9712×780=9360=96.797

The factors will be on either side of 96.796.7, about 37/2372 bigger or smaller.

37/2 = 18.5372=18.5

97 -18 =79 and 97+18 = 1159718=79and97+18=115

Use trial and error with values close to 79 and 11579and115

93609360 is not divisible by 7979

9360 div 80 = 117" "9360÷80=117 BINGO! " "117-80 = 37 11780=37

These are the factors, now we need to form them from 12 and 78012and780

" "12 and 780 12and780
" "darrcolor(white)(xxx)darr ×x
" "3color(white)(xxxx)20" "rarr 4 xx20 = 80 3××20 4×20=80
" "4color(white)(xxxx)39" "rarr 3xx39 = ul117
color(white)(xxxxxxxxxxxxxxxxxxxxx)37

These are the factors, now fill in the signs to get -37 and -780

" "12 and 780
" "darrcolor(white)(xxx)darr
" "3color(white)(xxxx)+20" "rarr 4 xx+20 = +80
" "4color(white)(xxxx)-39" "rarr 3xx-39 = -ul117
color(white)(xxxx.xxxxxxxxxxxxxxxxxxxx)-37

(3x+20)(4x-39)=0

Set each factor equal to 0

3x+20 =0 " "rarr x =-20/3

4x-39 =0" "rarr x = 39/4