Solve for x?

Question

Solve for x?

${0.6}^{2 x - 1} = 2$ $0.6^(2x-1)=2$

2 Answers

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Answer 1 · 2017-07-23T23:22:02

$x = \frac{1}{2} (\frac{ln 2}{ln 0.6} + 1)$ $x=1/2(ln2/ln0.6+1)$

Explanation:

${0.6}^{2 x - 1} = 2$ $0.6^(2x-1)=2$

$(2 x - 1) ln 0.6 = ln 2$ $(2x-1)ln0.6=ln2$

$2 x - 1 = \frac{ln 2}{ln 0.6}$ $2x-1=ln2/ln0.6$

$x = \frac{1}{2} (\frac{ln 2}{ln 0.6} + 1)$ $x=1/2(ln2/ln0.6+1)$

Answer 2 · 2017-07-24T13:56:56

$x = - 0.17845$ $x=-0.17845$

Explanation:

${0.6}^{2 x - 1} = 2$ $0.6^(2x-1)=2$

$(2 x - 1) log 0.6 = log 2$ $(2x-1)log0.6=log2$

$2 x - 1 = \frac{log 2}{log 0.6}$ $2x-1=log2/log0.6$

$x = \frac{1}{2} (\frac{log 2}{log 0.6} + 1)$ $x=1/2(log2/log0.6+1)$

$= \frac{1}{2} (\frac{0.30103}{- 0.22185} + 1)$ $=1/2(0.30103/(-0.22185)+1)$

$= \frac{1}{2} (1 - 1.3569)$ $=1/2(1-1.3569)$

$= - 0.17845$ $=-0.17845$

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Solve for x?

${0.6}^{2 x - 1} = 2$ $0.6^(2x-1)=2$

2 Answers

Explanation:

Explanation:

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${0.6}^{2 x - 1} = 2$ $0.6^(2x-1)=2$