Solve it kindly?

A body of mass 3kg is under a force causes a displacement in it ,given by S=t^2/3S=t23(in meters). The work done by the force in 2s is what?

1 Answer
Jul 13, 2017

W = 8/3W=83 "J"J

Explanation:

We're asked to find the work done on a particle given its mass and position equation with time.

I'll solve it without using kinetic energy formulas, but via force and displacement. Take a look at The Useful G.'s response for a different approach.

The equation for the work WW done in a particle is the dot product of the force and displacement vectors:

W = vecF • vecsW=Fs

Since his motion is one-dimensional, we can also write this as

W = FsW=Fs

We can find the object's displacement at time t = 2t=2 "s"s by plugging in for #t# in the equation:

s = ((2)^2)/3 = 4/3s=(2)23=43 "m"m

To find the constant force that acts on the object, we can first find the acceleration as a function of time, by differentiating the position equation twice:

(d^2)/(dt^2) [(t^2)/3] = 2/3d2dt2[t23]=23

So the acceleration aa is constant at 2/323 "m/s"^2m/s2.

The force FF that acts is

F = ma = (3color(white)(l)"kg")(2/3color(white)(l)"m/s"^2) = color(red)(2F=ma=(3lkg)(23lm/s2)=2 color(red)("N"N

Now that we know the force FF and displacement ss, the work done by the force during this time is

W = (color(red)(2)color(white)(l)color(red)("N"))(4/3color(white)(l)"m") = color(blue)(8/3W=(2lN)(43lm)=83 color(blue)("J"J