Question

Some very hot rocks have a temperature of `340 ^o C` and a specific heat of `160 J/(Kg*K)`. The rocks are bathed in `72 L` of boiling water. If the heat of the rocks completely vaporizes the water, what is the minimum combined mass of the rocks?

Answer 1

the minimum combined mass of the rocks are 4256. 25kg

Explanation:

the heat necessary to completely vaporizes the water is
`Q=m*lamda`
`Q=72*2.27*10^6`
this heat due to the rock released
`Q=72*2.27*10^6=m*160*(340-100)`
`m=(72*2.27*10^6)/(160*240)`
`m=4256.25kg`