Question

Suppose a ball is kicked horizontally off a mountain with an initial speed of 9.37 m/s. If the ball travels a horizontal distance of 85.0 m, how tall is the mountain?

Answer 1

`403.1"m"`

Explanation:

First get the time of flight from the horizontal component of motion for which the velocity is constant:

`t=s/v=85/9.37=9.07"s"`

Now we can get the height using:

`h=1/2"g"t^2`

`:.h=0.5xx9.8xx9.07^2=403.1"m"`