Suppose that we roll two fair 6-sided dice. What is the probability that the two numbers rolled sum to 4?

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Answer 1 · 2018-06-26T19:09:22

$\frac{1}{12}$ $1/12$

Favorable outcomes/results to get a sum of $4$ $4$ when fair dices are tossed are

$(1, 3), (2, 2), (3, 1)$ $(1, 3), (2, 2), (3, 1)$

While, the total outcomes of two fair dices $= 6 \times 6 = 36$ $=6\times6=36$

hence, the probability to get a sum of 4

$= \frac{favorable outcomes}{total outcomes}$ $=\frac{\text{favorable outcomes}}{\text{total outcomes}}$

$= \frac{3}{36}$ $=\frac{3}{36}$

$= \frac{1}{12}$ $=1/12$