Suppose that $y$ $y$ varies directly as the square root of $x$ $x$ , and the $y = 43$ $y=43$ when $x = 324$ $x=324$ . What is $y$ $y$ when $x = 172$ $x=172$ ?

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Answer 1 · 2018-04-09T11:24:20

$y = \frac{43 \sqrt{43}}{9}$ $y=(43sqrt 43)/9$

$y \propto \sqrt{x} or y = k \cdot \sqrt{x}; k$ $y prop sqrt x or y = k *sqrt x ; k$ is variation constant.

$y=43 , x=324 :.y = k * sqrt x or 43 = k* sqrt 324$ or

$43 = k* 18 :. k= 43/18 :.$ The variation equation is

$y = 43/18 * sqrt x ; x=172 , y= ?$

$y = 43/18 * sqrt 172 =43/18 *2 sqrt 43$ or

$y=(43sqrt 43)/9$ [ Ans]

Suppose that yyy varies directly as the square root of xxx, and the y=43y=43y=43 when x=324x=324x=324. What is yyy when x=172x=172x=172?