Suppose your license plate has three digits (between 0 and 9) followed by three letters (between A and Z). If a license number is selected randomly, what is the probability that yours is the one selected?

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Answer 1 · 2017-12-06T01:06:53

#1/(17,576,000)#

For each space, we have either a number (3 spaces with 10 choices in each) or a letter (3 spaces with 26 choices each). That means that there are:

#10^3xx26^3=17,576,000# plates.

We have one plate in all of possibilities, and so the probability of having ours picked is:

#1/(17,576,000)#