The air inside a beach ball is at a temp of 25 degrees Celsius, and a pressure of 1.0 atm. If the ball contains .85 mol of air what is the volume?

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The air inside a beach ball is at a temp of 25 degrees Celsius, and a pressure of 1.0 atm. If the ball contains .85 mol of air what is the volume?

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Answer 1 · 2018-06-04T12:04:02

Approx. $20 \cdot L$ $20*L$ ....

Explanation:

We simply solve for $V$ $V$ in the Ideal Gas equation...

$V = \frac{n R T}{P} = \frac{0.85 \cdot m o l \times 0.0821 \cdot \frac{L \cdot a t m}{K \cdot m o l} \times 298 \cdot K}{1.0 \cdot a t m}$ $V=(nRT)/P=(0.85*molxx0.0821*(L*atm)/(K*mol)xx298*K)/(1.0*atm)$

$= ? ? \cdot L$ $=??*L$ ....

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The air inside a beach ball is at a temp of 25 degrees Celsius, and a pressure of 1.0 atm. If the ball contains .85 mol of air what is the volume?

1 Answer

Explanation:

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