The concentration of carbon monoxide in an urban apartment is 48 $μ$ $mu$ g/ $m^{3}$ $m^3$ . What mass of carbon monoxide in grams is present in a room measuring 10.6 ft X 14.8 ft X 20.5 ft?

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The concentration of carbon monoxide in an urban apartment is 48 $μ$ $mu$ g/ $m^{3}$ $m^3$ . What mass of carbon monoxide in grams is present in a room measuring 10.6 ft X 14.8 ft X 20.5 ft?

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Answer 1 · 2016-09-01T10:50:45

Approx. $5$ $5$ $m g$ $mg$

Explanation:

$1 metre = 3.048 feet$ $"1 metre = 3.048 feet"$

Volume of room $=$ $=$ $10.6 \times 14.8 \times 20.5 \cdot f t^{3} \times \frac{1}{{(3.048 \cdot f t \cdot m^{- 1})}^{3}}$ $10.6xx14.8xx20.5*ft^3xx1/(3.048*ft*m^-1)^3$

$=$ $=$ $113.57 \cdot m^{3}$ $113.57*m^3$

And thus mass of $C O$ $CO$ $=$ $=$ $113.57 \cdot m^{3} \times 48 \times 10^{- 6} \cdot g \cdot m^{- 3}$ $113.57*m^3xx48xx10^-6*g*m^-3$

$=$ $=$ $5.45 \times 10^{- 3} g$ $5.45xx10^-3g$

Do not assume that I have got my arithmetic right; you are obliged to check this result.

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The concentration of carbon monoxide in an urban apartment is 48 $μ$ $mu$ g/ $m^{3}$ $m^3$ . What mass of carbon monoxide in grams is present in a room measuring 10.6 ft X 14.8 ft X 20.5 ft?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

The concentration of carbon monoxide in an urban apartment is 48 μmug/m3m^3. What mass of carbon monoxide in grams is present in a room measuring 10.6 ft X 14.8 ft X 20.5 ft?

1 Answer

Explanation:

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The concentration of carbon monoxide in an urban apartment is 48 $μ$ $mu$ g/ $m^{3}$ $m^3$ . What mass of carbon monoxide in grams is present in a room measuring 10.6 ft X 14.8 ft X 20.5 ft?