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The density of silver (Ag) is 10.5000 g/cm^3. How do you find of Ag that occupies 965 cm^3 of space?

1 Answer

Sep 26, 2016

To find the mass, multiply the density by the volume.

Explanation:

$ρ, density$ $rho,"density"$ $=$ $=$ $\frac{Mass}{Volume}$ $"Mass"/"Volume"$ .

And thus $Mass$ $"Mass"$ $=$ $=$ $ρ \times volume$ $rhoxx"volume"$

$=$ $=$ $10.500 \cdot g \cdot c m^{- 3} \times 965 \cdot c m^{3}$ $10.500*g*cm^-3xx965*cm^3$

$=$ $=$ $10132.5 \cdot g$ $10132.5*g$ .

Silver currently sells for $$ 0 - 63 USD g^{- 1}$ $$0-63" USD "g^-1$ . How much is your lump worth?

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