The empirical formula is $C_{5} H_{4}$ $C_5H_4$ and its molar mass is 128.16 g/mol. What is the molecular formula?

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The empirical formula is $C_{5} H_{4}$ $C_5H_4$ and its molar mass is 128.16 g/mol. What is the molecular formula?

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Answer 1 · 2016-02-14T15:59:17

The molecular formula is $C_{10} H_{8}$ $C_10H_8$ . How do we know?

Explanation:

The molecular formula is ALWAYS a mulitple of the empirical formula. Of course, the multiple might be $1$ $1$ .

So $MF = {(E F)}_{n}$ $"MF" =(EF)_n$ $=$ $=$ ${(5 \times 12.011 \cdot g \cdot m o l^{- 1} + 4 \times 1.00794 \cdot g \cdot m o l^{- 1})}_{n}^{- 1}$ $(5xx12.011*g*mol^-1+ 4xx1.00794*g*mol^-1)_n$ $=$ $=$ $(64.08) g \cdot m o l^{- 1} \times n = 128.16 \cdot g \cdot m o l^{- 1} .$ $(64.08)g*mol^-1xxn= 128.16*g*mol^-1.$

Clearly, $n = 2$ $n=2$ , and molecular formula $=$ $=$ $C_{10} H_{8}$ $C_10H_8$ , probably napthalene.

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The empirical formula is $C_{5} H_{4}$ $C_5H_4$ and its molar mass is 128.16 g/mol. What is the molecular formula?

1 Answer

Explanation:

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The empirical formula is C5H4C_5H_4 and its molar mass is 128.16 g/mol. What is the molecular formula?

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The empirical formula is $C_{5} H_{4}$ $C_5H_4$ and its molar mass is 128.16 g/mol. What is the molecular formula?