The experimental calculation of the specific heat of aluminum was found to be 156 cal/g °C, but the actual value was given as 185 cal/g°C. What is the percent error?

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The experimental calculation of the specific heat of aluminum was found to be 156 cal/g °C, but the actual value was given as 185 cal/g°C. What is the percent error?

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Answer 1 · 2018-01-27T10:05:41

$= 16 %$ $=16%$

Explanation:

This problem can be solve using the formula shown below.

$% error = \frac{absolute error}{actual value} \times 100$ $%"error"="absolute error"/"actual value"xx100$

$w h e r e :$ $where:$

$absolute error = actual value - experimental value$ $"absolute error"="actual value"-"experimental value"$
$absolute error = \frac{185 c a l}{g \cdot^{o} C} - \frac{156 c a l}{g \cdot^{o} C}$ $"absolute error"=(185cal)/(g*^oC)-(156cal)/(g*^oC)$
$absolute error = \frac{29 c a l}{g \cdot^{o} C}$ $"absolute error"=(29cal)/(g*^oC)$

Knowing the absolute error, % error can be calculated using the formula described above. Plug in the given and the calculated values as shown below.

$% error = \frac{absolute error}{actual percentage} \times 100$ $%"error"="absolute error"/"actual percentage"xx100$
$%"error"=(29cancel((cal)/(g*^oC)))/(185cancel((cal)/(g*^oC)))xx100$
$%"error"=0.16xx100$
$%"error"=16%$

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The experimental calculation of the specific heat of aluminum was found to be 156 cal/g °C, but the actual value was given as 185 cal/g°C. What is the percent error?

1 Answer

Explanation:

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