The force applied on a moving object with a mass of #2 kg # on a linear path is given by #F(x)=x+3#. How much work would it take to move the object over #x in [0,2 ] #?

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Answer 1 · 2017-04-05T06:28:03

The work done is #=8J#

The mass is #m=2kg#

The force applied is

#F(x)=x+3#

The work done is

#W=F*d#

#d# is the distance

So,

#W=intF(x)dx#

#=int_0^2(x+3)dx#

#=[1/2x^2+3x]_0^2#

#=(2+6)-(0)#

#=8J#