The formula for the illegal drug cocaine is #C_17H_21NO_4#, which is 303.39 g/mol. What is the percentage of carbon in the compound?

1 Answer
anor277
May 5, 2016

Approx. 70%

Explanation:

#"%Carbon"# #=# #"Mass of carbon"/"Mass of molecule"# #xx100%#

#=# #(17xx12.011*g*mol^-1)/(303.39*g*mol^-1)# #xx100%# #=# #??%#

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