The cost function for a product is C(x)=0.8x^2 +120x+110. How to find average cost over [0,600] ?

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Answer 1 · 2016-03-05T20:24:27

$C_(avg)=barC=1/600int_0^600C(x)dx=132110$

The average cost over this interval may be given by

$C_(avg)=1/(600-0)int_0^600C(x)dx$

$=1/600int_0^600 (0.8x^2+120x+110)dx$

$=1/600 [ (0.8x^3)/3+(120x^2)/2+110x]_0^600$

$=1/600[57600000+21600000+66000-0]$

$=132110$ .