The Jurassic Zoo charges $12 for each adult admission and $6 for each child. The total bill for the 205 people from a school trip was $1590. How many adults and how many children went to the zoo?

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Answer 1 · 2016-12-29T16:05:57

$60$ $60$ adults and $145$ $145$ children went to the zoo.

Let us assume number of adults are $a$ $a$ ,

hence number of children are $205 - a$ $205-a$

As Jurassic Zoo charges $$ 12$ $$12$ for each adult admission and $$ 6$ $$6$ for each child,

the total bill is $12 \times a + (205 - a) \times 6 = 12 a + 1230 - 6 a = 6 a + 1230$ $12xxa+(205-a)xx6=12a+1230-6a=6a+1230$

but bill is $$ 1590$ $$1590$

Hence $6 a + 1230 = 1590$ $6a+1230=1590$

or $6 a = 1590 - 1230 = 360$ $6a=1590-1230=360$

or $a = \frac{360}{6} = 60$ $a=360/6=60$

Hence $60$ $60$ adults and $(205 - 60) = 145$ $(205-60)=145$ children went to the zoo.