The kinetic energy of an object with a mass of 1 kg constantly changes from 126 J to 702 J over 9 s. What is the impulse on the object at 5 s?

1 Answer
Apr 16, 2016

Cannot be answered

Explanation:

K.E. = k*t

=> v = sqrt((2k)/m) sqrt(t)

=> int_i^f m dv = int_t^(t+5) sqrt(k/2m) dt/sqrt(t)

So to have an absolute value of the impulse, we need to specify which 5s we are talking about.