The length of a rectangular garden is 3 yd more than twice its width. The perimeter of the garden is 30 yd What are the width and length of the garden?

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Answer 1 · 2016-11-04T10:57:43

The width of the rectangular garden is 4yd and the length is 11yd.

For this problem let's call the width $w$ . Then the length which is "3 yd more than twice its width" would be $(2w + 3)$ .

The formula for the perimeter of a rectangle is: $p = 2w *+ 2l$

Substituting the information provided gives:

$30 = 2w + 2(2w + 3)$

Expanding what is in parenthesis, combining like terms and then solving for $w$ while keeping the equation balanced gives:

$30 = 2w + 4w + 6$

$30 = 6w + 6$

$30 - 6 = 6w + 6 - 6$

$24 = 6w$

$24/6 = (6w)/6$

$w = 4$

Substituting the value of $w$ into the relationship for length gives:

$l = (2*4) + 3$

$l = 8 + 3$

$l = 11$