The line L1 has equation 4y+3=2x. The point A (p,4) lies on L1. How do you find the value of the constant p?

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The line L1 has equation 4y+3=2x. The point A (p,4) lies on L1. How do you find the value of the constant p?

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Answer 1 · 2016-12-15T05:08:44

Value of constant $p$ $p$ is $9.5$ $9.5$ .

Explanation:

As the point $A (p, 4)$ $A(p,4)$ lies on L1, whose equation is $4 y + 3 = 2 x$ $4y+3=2x$ . if we substitute values of $x$ $x$ and $y$ $y$ given by the coordinates of $A$ $A$ , it should satisfy the equation.

i.e. $4 \times 4 + 3 = 2 \times p$ $4xx4+3=2xxp$

or $16 + 3 = 2 p$ $16+3=2p$

or $2 p = 19$ $2p=19$

i.e. $p = \frac{19}{2} = 9.5$ $p=19/2=9.5$

Hence, value of constant $p$ $p$ is $9.5$ $9.5$ .

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The line L1 has equation 4y+3=2x. The point A (p,4) lies on L1. How do you find the value of the constant p?

1 Answer

Explanation:

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