. The mineral manganosite is a compound of manganese-55 and oxygen-16. If 77% of the mass of manganosite is due to manganese, what is the empirical formula of manganosite?

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. The mineral manganosite is a compound of manganese-55 and oxygen-16. If 77% of the mass of manganosite is due to manganese, what is the empirical formula of manganosite?

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Answer 1 · 2016-11-05T20:31:00

$Manganosite$ $"Manganosite"$ has an empirical formula of $M n O$ $MnO$

Explanation:

Typically with these problems, we assume a mass of $100 \cdot g$ $100*g$ of compound, and we work out the empirical formula on this basis.

$Moles of^{55} M n$ $"Moles of " ""^55Mn$ $=$ $=$ $\frac{77.0 \cdot g}{55.0 \cdot g \cdot m o l^{- 1}}$ $(77.0*g)/(55.0*g*mol^-1)$ $=$ $=$ $1.40 \cdot m o l .$ $1.40*mol.$

$Moles of^{16} O$ $"Moles of " ""^16O$ $=$ $=$ $\frac{23.0 \cdot g}{16.0 \cdot g \cdot m o l^{- 1}}$ $(23.0*g)/(16.0*g*mol^-1)$ $=$ $=$ $1.44 \cdot m o l .$ $1.44*mol.$

These are tolerably close to equimolar quantities, and thus the empirical formula is $M n O$ $MnO$ .

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. The mineral manganosite is a compound of manganese-55 and oxygen-16. If 77% of the mass of manganosite is due to manganese, what is the empirical formula of manganosite?

1 Answer

Explanation:

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