The number of cars (c) in a parking lot increases when the parking fee (f) decreases. How do you write the correct equation for this scenario, and solve for the number of cars when the fee is $6?

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Answer 1 · 2018-01-15T12:29:29

The correct equation for this scenario is $c = k \times \frac{1}{f}$ $c= k xx 1/f$ , where $k$ $k$ is the proportionality constant.

The number of cars when the fee is $6 will be $c = \frac{k}{6}$ $c = k/6$

The number of cars ( $c$ $c$ ) in a parking lot increases when the parking fee ( $f$ $f$ ) decreases.

This indicates inverse variation. We can write the proportionality equation as :

$c \propto \frac{1}{f}$ $c prop 1/f$

And the equation after removing the proportionality sign can be written as :

$c = k \times \frac{1}{f}$ $c= k xx 1/f$ , where $k$ $k$ is the proportionality constant.

The number of cars when the fee is $6 will be :

$c = \frac{k}{6}$ $c = k/6$