The partial pressures of the gases in a miture are 0.00461 atm $O_{2}$ $O_2$ , 1.78 atm $N_{2}$ $N_2$ , and 0.975 atm $A r$ $Ar$ . What is the total pressure of the mixture?

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The partial pressures of the gases in a miture are 0.00461 atm $O_{2}$ $O_2$ , 1.78 atm $N_{2}$ $N_2$ , and 0.975 atm $A r$ $Ar$ . What is the total pressure of the mixture?

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Answer 1 · 2017-03-31T08:03:38

The total pressure is simply the sum of the individual partial pressures..........

Explanation:

$P_{Total} = P_{O_{2}} + P_{N_{2}} + P_{A r}$ $P_"Total"=P_(O_2)+P_(N_2)+ P_(Ar)$

$= (4.61 \times 10^{- 2} + 1.78 + 0.975) \cdot a t m$ $=(4.61xx10^-2 + 1.78+0.975)*atm$

$≅ 2.76 \cdot a t m$ $~=2.76*atm$

This is a simple result of $Dalton's Law of Partial Pressure$ $"Dalton's Law of Partial Pressure"$ , for which [see here.](https://socratic.org/questions/how-would-you-define-and-explain-dalton-s-law-of-partial-pressure)

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The partial pressures of the gases in a miture are 0.00461 atm $O_{2}$ $O_2$ , 1.78 atm $N_{2}$ $N_2$ , and 0.975 atm $A r$ $Ar$ . What is the total pressure of the mixture?

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Explanation:

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The partial pressures of the gases in a miture are 0.00461 atm O2O_2, 1.78 atm N2N_2, and 0.975 atm ArAr. What is the total pressure of the mixture?

1 Answer

Explanation:

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The partial pressures of the gases in a miture are 0.00461 atm $O_{2}$ $O_2$ , 1.78 atm $N_{2}$ $N_2$ , and 0.975 atm $A r$ $Ar$ . What is the total pressure of the mixture?