The perimeter of a rectangle is 162 ft. The lenght is 3 more than twice the width. How do you find the dimensions of the rectangle?

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The perimeter of a rectangle is 162 ft. The lenght is 3 more than twice the width. How do you find the dimensions of the rectangle?

1 Answer

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Answer 1 · 2015-09-25T13:45:58

Width: $26 ft$ $"26 ft"$
Length: $55 ft$ $"55 ft"$

Explanation:

Let the length be $l$ $l$
Let the width be $w$ $w$

$l = 2 w + 3$ $l = 2w + 3$

$2 (l + w) = 162$ $2(l+w) = 162$

$2 w + 3 + w = \frac{162}{2}$ $2w + 3 + w = 162/2$

$3 w + 3 = 81$ $3w + 3 =81$

$3 w = 78$ $3w = 78$

$w = 26 ft$ $w = "26 ft"$

This means that

$l = 2 w + 3$ $l = 2w + 3$

$l = 2 (26) + 3$ $l = 2(26) + 3$

$l = 55 ft$ $l = "55 ft"$

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The perimeter of a rectangle is 162 ft. The lenght is 3 more than twice the width. How do you find the dimensions of the rectangle?

1 Answer

Explanation:

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