The perimeter of an equilateral triangle is 45 centimeters. How do you find the length of an altitude of the triangle?

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The perimeter of an equilateral triangle is 45 centimeters. How do you find the length of an altitude of the triangle?

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Answer 1 · 2016-02-08T22:38:43

A triangle with 45 cm of perimeter has 15 cm of side. The
"altitude" connects the middle of one side to the opposite vertice. This forms a rectangle triangle with hypothenuse 15 cm and the small catet a= 7.5 cm. So by the Pythagoras theorem we must solve the equation:

${7.5}^{2} + b^{2} = 15^{2}$ $7.5^2+b^2=15^2$

$b = \sqrt{225 - 56.25} = \sqrt{168.75} = 12.99 c m$ $b=sqrt(225-56.25)=sqrt(168.75)=12.99 cm$

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The perimeter of an equilateral triangle is 45 centimeters. How do you find the length of an altitude of the triangle?

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