The points (10, -8) and (9, t) fall on a line with a slope of 0. what is the value of t?

1 Answer
Dec 16, 2016

t=-8t=8

Explanation:

gradient (slope) =("change in up or down")/("change in along")" "=change in up or downchange in along

as you travel from left to right on the x-axis.

If gradient = 0 then we have:

("change in up or down")/("change in along")" " = (y_2-y_1)/(x_2-x_1)=0/(x_2-x_1)change in up or downchange in along =y2y1x2x1=0x2x1

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If the gradient is 0 then the line is horizontal. Thus the value of yy is constant (y_2=y_1)(y2=y1)

Given that point 1 " "P_1->(x_1,y_1)=(10,-8) P1(x1,y1)=(10,8)

Then the constant value of y is -8
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However, the question uses the letter tt instead of yy so
tt is a constant at t=-8t=8