The position of an object moving along a line is given by #p(t) = t-cos(( pi )/4t) #. What is the speed of the object at #t = 2 #?

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Answer 1 · 2016-05-03T15:36:11

#v(2)=(4+pi)/4#

#v(t)=d/(d t) p(t)#

#v(t)=d/(d t)(t-cos(pi/4 *t))#

#v(t)=1+pi/4*sin(pi/4*t)#

#"for t=2 " ->v(2)=1+pi/4*sin(pi/4*2) #

#v(2)=1+pi/4*1#

#v(2)=1+pi/4#

#v(2)=(4+pi)/4#