The pressure in a bicycle tire is 1.34 atm at 33.0°C. At what temperature will the pressure inside the tire be 1.60 atm if volume is constant?

1 Answer
Dec 22, 2015

The temperature will be 366 K.

Explanation:

This is an example of Gay-Lussac's law in which the pressure and Kelvin temperature are directly proportional at constant volume. The equation to use is P_1/T_1=P_2/T_2P1T1=P2T2.

P_1="1.34 atm"P1=1.34 atm
T_1="33.0"^"o""C"+273.15="306.2 K"T1=33.0oC+273.15=306.2 K
P_2="1.60 atm"P2=1.60 atm
T_2="???"T2=???

Solution
Rearrange the equation to isolate T_2T2 and solve.
P_1/T_1=P_2/T_2P1T1=P2T2

T_2=(P_2T_1)/P_1T2=P2T1P1

T_2=(1.60cancel"atm"xx306.2"K")/(1.34cancel"atm")

T_2="366 K"