Question

The pressure in a container is 8 atm at a temperature of 75°C. If the temperature is changed to 25°C what would be the new pressure?

Answer 1

The new pressure is `=6.85 atm`

Explanation:

We apply Gay Lussac's Law

`P_1/T_1=P_2/T_2`

`P_1=8 atm`

`T_1=75+273=348K`

`T_2=25+273=298K`

`P_2=T_2/T_1*P_1`

`=298/348*8`

`=6.85 atm`