The punter stands on the 22 yard (roughly a meter) line to the left of the 50 yard line and the ball is kicked with an initial velocity of 25.3 m/s at an angle of 58.5° above the ground. How far from the punter is the football when it's at its max height?

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Answer 1 · 2015-09-25T16:36:09

#29.1"m"#

To find the time to reach maximum height use:

#v=u+at#

The vertical component of velocity is #Vsintheta# where #theta# is the angle to the ground.

#a=g=-9.8"m/s/s"#

So this becomes:

#0=25.3sin(58.5)-9.8t#

#t=(-21.57)/(-9.8)=2.2"s"#

The horizontal component of velocity is a constant #25.3cos(58.5)#.

So distance = velocity x time:

#d=25.3cos(58.5)xx2.2=29.1"m"#