Question

The punter stands on the 22 yard (roughly a meter) line to the left of the 50 yard line and the ball is kicked with an initial velocity of 25.3 m/s at an angle of 58.5° above the ground. How far from the punter is the football when it's at its max height?

Answer 1

`29.1"m"`

Explanation:

To find the time to reach maximum height use:

`v=u+at`

The vertical component of velocity is `Vsintheta` where `theta` is the angle to the ground.

`a=g=-9.8"m/s/s"`

So this becomes:

`0=25.3sin(58.5)-9.8t`

`t=(-21.57)/(-9.8)=2.2"s"`

The horizontal component of velocity is a constant `25.3cos(58.5)`.

So distance = velocity x time:

`d=25.3cos(58.5)xx2.2=29.1"m"`