The solubility of manganese(II) sulphate at 20oC is 62.9g/100g H2O. How many grams of manganous(II)sulphate penta-hydrate crystal must be added to 51L H2O to make a saturated solution?

1 Answer
Oct 25, 2017

Well you gots 51*L water.....and you need approx. 51*kg of the hydrate.....

Explanation:

And we got 51*Lxx1000*g*"water"*L^-1xx(62.9*g*"salt")/(100*g*"water")

=32079*g

And so we need to add a trifle over 32*kg with respect to MnSO_4(s).....i.e. (32.08xx10^3*g)/(152.0*g*mol^-1)=211.05*mol.

And with respect to the pentahydrate, this represents a mass of....

211.05*molxx241.05*g*mol^-1=50.9*kg....

And by the way what does "saturated solution" mean?