The solubility product constant for #"Mg(OH)"_2# is #1.8 × 10^"-11"#. What would be the solubility of #"Mg(OH)"_2# in 0.345 M #"NaOH"#?
The solubility product constant for #"Mg(OH)"_2# is #1.8 × 10^"-11"# . What would be the solubility of #"Mg(OH)"_2# in 0.345 M #"NaOH"# ?
The solubility product constant for
1 Answer
The solubility would be
Explanation:
Set up the chemical equation for the equilibrium:
Set up the solubility product expression:
Check that
Solve the
∴ Solubility of