Question

The sum of four consecutive even integers is 84, what are the integers?

Answer 1

Suppose the integers are `n`, `n+2`, `n+4` and `n+6`

Then

`84=n+(n+2)+(n+4)+(n+6) = 4n+12`

Subtract `12` from both ends to get

`72 = 4n`

Divide both ends by `4` to get

`n = 18`

So the integers are: `18`, `20`, `22`, `24`