Question

The sum of four consecutive integers is 2174. How do you find the numbers?

Answer 1

You can take the 1st integer as `x` and other consecutive integers as `x+1, x+2,x+3`

Sum up and find the value of `x`, then we get the values of the other integers.

Explanation:

Let the 1st integer be `x`, next consecutive integers will be (`x+1), (x+2) and (x+3).`

Now,
`x+(x+1)+(x+2)+(x+3)=2174`

or,`4x+6=2174`

or, `4x=2174-6`

or, `4x=2168`

or, `x=2168/4`

or, `x= 542`

So,
`x+1= 543`

`x+2=544`

`x+3=545`

The four consecutive integers are `542,543,544,545.`

Answer 2

Four consecutive integers :`542,543,544,545.`

Explanation:

Let the four consecutive integers:

`n,n+1,n+2,n+3.`

Given that,

Sum=2174,

`=>n+(n+1)+(n+2)+(n+3)=2174`

`=>4n+6=2174`

`=>4n=2168`

`=>n=542`

So,

`n+1=542+1=543`

`n+2=542+2=544`

`n+3=542+3=545`

Hence, four consecutive integers :`542,543,544,545.`

Answer 3

The numbers are `" "542," "543," "544," "545`

Explanation:

Consecutive numbers are those that follow each other like 17,18,19,... They differ by `1`.

Let the numbers be `" "x," "x+1," "x+2," "x+3`

Their sum is `2174`

`x+x+1+x+2+x+3=2174`

`4x + 6 = 2174`

`4x = 2174 -6`

`4x = 2168`

`x = 542`

The first number is `542.`

The numbers are `" "542," "543," "544," "545`