The sum of four consecutive integers is -42. What are the numbers?

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The sum of four consecutive integers is -42. What are the numbers?

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Answer 1 · 2016-05-10T09:33:36

Start by using variables to define the numbers.
Let the smallest integer be $x$ $x$ .

The other integers are therefore $(x + 1), (x + 2) and (x + 3)$ $(x+1), (x+2) and (x + 3)$

Their sum is -42

$x + x + 1 + x + 2 + x + 3 = - 42 simplify and solve$ $x +x+1 + x+2 + x+3 = -42 " simplify and solve"$

$4 x + 6 = - 42$ $4x + 6 = -42$
$4 x = - 42 - 6$ $4x = -42 - 6$
$4 x = - 48$ $4x = -48$
$x = - 12 this is the smallest integer$ $x = -12 " this is the smallest integer"$

The integers are -12 -11 -10 and -9.

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The sum of four consecutive integers is -42. What are the numbers?

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