The sum of sixteen and six times a number t is eighty-two. What is the number?

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Answer 1 · 2016-12-06T16:29:23

$t = 11$ $t = 11$

First, let's write the equation we need to solve one step at a time:

"six times a number $t$ $t$ " can be written as:

$6 \cdot t$ $6*t$

Then, "The sum of sixteen and " this number can be written as:

$(6 \cdot t) + 16$ $(6*t) + 16$

Finally, this term "is eighty-two" gives us:

$(6 \cdot t) + 16 = 82$ $(6*t) + 16 = 82$

We can now solve for $t$ $t$ :

$(6 \cdot t) + 16 - 16 = 82 - 16$ $(6*t) + 16 - 16 = 82 - 16$

$(6 \cdot t) + 0 = 66$ $(6*t) + 0 = 66$

$6 t = 66$ $6t = 66$

$\frac{6 t}{6} = \frac{66}{6}$ $(6t)/6 = 66/6$

$(cancel(6)t)/cancel(6) = 11$

$t = 11$