The sum of three consecutive integers is 135. What are the numbers?
1 Answer
Jul 4, 2017
Explanation:
"let the first integer be represented by " nlet the first integer be represented by n
"then the second integer will be " n+1then the second integer will be n+1
"and the third integer " n+2and the third integer n+2
rArrn+n+1+n+2=135larrcolor(blue)" sum of integers"⇒n+n+1+n+2=135← sum of integers
rArr3n+3=135larrcolor(blue)" simplifying left side"⇒3n+3=135← simplifying left side
"subtract 3 from both sides"subtract 3 from both sides
3ncancel(+3)cancel(-3)=135-3
rArr3n=132
"divide both sides by 3"
(cancel(3) n)/cancel(3)=132/3
rArrn=44
rArrn+1=44+1=45
rArrn+2=44+2=46
"the three consecutive integers are " 44,45,46
color(blue)"As a check"
44+45+46=135rarr" True"