The sum of three consecutive integers is 135. What are the numbers?

1 Answer
Jul 4, 2017

44,45,4644,45,46

Explanation:

"let the first integer be represented by " nlet the first integer be represented by n

"then the second integer will be " n+1then the second integer will be n+1

"and the third integer " n+2and the third integer n+2

rArrn+n+1+n+2=135larrcolor(blue)" sum of integers"n+n+1+n+2=135 sum of integers

rArr3n+3=135larrcolor(blue)" simplifying left side"3n+3=135 simplifying left side

"subtract 3 from both sides"subtract 3 from both sides

3ncancel(+3)cancel(-3)=135-3

rArr3n=132

"divide both sides by 3"

(cancel(3) n)/cancel(3)=132/3

rArrn=44

rArrn+1=44+1=45

rArrn+2=44+2=46

"the three consecutive integers are " 44,45,46

color(blue)"As a check"

44+45+46=135rarr" True"